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AvengersAgeOfUltronmoviehindidubbed[VERIFIED] Download720phd - ส.หวังเจริญมอเตอร์

AvengersAgeOfUltronmoviehindidubbed[VERIFIED] Download720phd

AvengersAgeOfUltronmoviehindidubbed[VERIFIED] Download720phd


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AvengersAgeOfUltronmoviehindidubbeddownload720phd

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How to find out if this code get’s executed twice

How to find out if this code gets executed twice (some sort of loop is executed twice) for a given argument in the following code?
extern “C” {
#include
}

struct foo {
int a;
};

void bar(int foo_stuff)
{
printf(”
%d”, foo_stuff.a);
}

int main(int argc, char** argv)
{
struct foo f;
f.a = argc;
bar(f);
return 0;
}

A:

That’s actually undefined behavior, you are not allowed to modify a struct member from outside the object the way you are doing.
You can use memcpy(&f, &foo, sizeof(f)), that should do the trick for you.
The reason it is undefined behavior is because the struct foo’s field will be interpreted as char * or unsigned char *, which might be part of a bigger structure.
Your example will probably not execute twice if the argument is interpreted as a pointer, if it’s a pointer to a struct with a field of type int, it can be interpreted as a pointer to an array of that int type, though.

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